Find the net forces from the following diagram.
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Answered by
284
Hey there!
Net force=Sum of Forces of x direction - Sum of Force of -x [Opposite direction of x] forces
a) Net force
=(10+8)-12
=18-12
=6N
b)Net force
=8-8
=0N
c) Net force
=(8+6)-0
=14N
d)Net force
=9-8
=1N
Note :- In (a),(b)(c) Net force is taken with west as reference So, the body will move with the net force in the direction of West
In (d), Net force is taken with north as reference.
hope helped!
Net force=Sum of Forces of x direction - Sum of Force of -x [Opposite direction of x] forces
a) Net force
=(10+8)-12
=18-12
=6N
b)Net force
=8-8
=0N
c) Net force
=(8+6)-0
=14N
d)Net force
=9-8
=1N
Note :- In (a),(b)(c) Net force is taken with west as reference So, the body will move with the net force in the direction of West
In (d), Net force is taken with north as reference.
hope helped!
Answered by
102
Answer:
Explanation:
Hey there!
Net force=Sum of Forces of x direction - Sum of Force of -x [Opposite direction of x] forces
a) Net force
=(10+8)-12
=18-12
=6N
b)Net force
=8-8
=0N
c) Net force
=(8+6)-0
=14N
d)Net force
=9-8
=1N
Note :- In (a),(b)(c) Net force is taken with west as reference So, the body will move with the net force in the direction of West
In (d), Net force is taken with north as reference.
hope it helped!
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