Question

find the net forces from the following diagrams free body diagram 6N 6N 3N 20N ​

Answer 1

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Two forces of 6N and 3N are acting on the two blocks of masses 2kg and 1kg respectively kept on friction less horizontal floor. The force exerted on 2kg block by 1kg block is:

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Correct option is C)

Let F be force exerted on 2kg block by 1kg block,

So Free body diagram:

For 2kg block,

6−F=2×a−−−(1)

where a is the acceleration of two blocks

For 1kg block

F−3=1×a⇒a=F−3

Put this value in equation (1)

6−F=2×(F−3)⇒3F=12⇒F=4N