Question

find the net torque acting on the rod and its direction, if: r =3m and force =30N pivot r=2m and force = 20N​

Answer 1

Answer:

We know that Torque is the product of Force and perpendicular distance (or) radius. Here let us consider F1= 30N, F2=20N and R1= 3m , R2= 2m.

Now, Torque (T1) = F1×r1, T1= 30N×3m, T1= 90Nm

Torque (T2)= F2×r2, T2= 20N×2m, T2= 40Nm

Now, Net torque (T)= T1+T2, (T) = (90+40)Nm

T= 130Nm, Hence the net Torque is 130Nm. Hope this helps you.