Question

find the net torque acting on the rod and its direction, if: r =3m and force =30N pivot r=2m and force = 20N​

Answer 1

net torque =T1 -T2

$= (r1 \times t1) - (r2 \times T2) = (3 \times 30) - (2 \times 20) = 90 - 40 = 50$

Net torque = 50

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Answer 2

Answer:

net torque =T1 -T2

= (r1 \times t1) - (r2 \times T2) = (3 \times 30) - (2 \times 20) = 90 - 40 = 50=(r1×t1)−(r2×T2)=(3×30)−(2×20)=90−40=50

Net torque = 50

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