Find the net torque. The answer is 4Fd. I need explanation. Plz answer fast...
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Answer:
Torque is the wedge product of the radial vector from the axis of rotation to the point at which the force is applied and the force vector. I.e. $${\bf\unicode[STIXGeneral]{x03c4}} = \mathbf r \wedge \mathbf F$$
Torque is the wedge product of the radial vector from the axis of rotation to the point at which the force is applied and the force vector. I.e. $${\bf\unicode[STIXGeneral]{x03c4}} = \mathbf r \wedge \mathbf F$$enter image description here
Torque is the wedge product of the radial vector from the axis of rotation to the point at which the force is applied and the force vector. I.e. $${\bf\unicode[STIXGeneral]{x03c4}} = \mathbf r \wedge \mathbf F$$enter image description hereThe net torque will be the sum of all the torques added (bi)vectorially.
Torque is the wedge product of the radial vector from the axis of rotation to the point at which the force is applied and the force vector. I.e. $${\bf\unicode[STIXGeneral]{x03c4}} = \mathbf r \wedge \mathbf F$$enter image description hereThe net torque will be the sum of all the torques added (bi)vectorially.In this case you have $${\bf\unicode[STIXGeneral]{x03c4}} = (0.1\,\mathbf{\hat x}\textrm{ m})\wedge (-10\,\mathbf{\hat y}\textrm{ N}) + (0.7\,\mathbf{\hat x}\textrm{ m})\wedge (-15\,\mathbf{\hat y}\textrm{ N}) = -11.5\,\mathbf{\hat x}\wedge\mathbf{\hat y}\textrm{ Nm}$$
Torque is the wedge product of the radial vector from the axis of rotation to the point at which the force is applied and the force vector. I.e. $${\bf\unicode[STIXGeneral]{x03c4}} = \mathbf r \wedge \mathbf F$$enter image description hereThe net torque will be the sum of all the torques added (bi)vectorially.In this case you have $${\bf\unicode[STIXGeneral]{x03c4}} = (0.1\,\mathbf{\hat x}\textrm{ m})\wedge (-10\,\mathbf{\hat y}\textrm{ N}) + (0.7\,\mathbf{\hat x}\textrm{ m})\wedge (-15\,\mathbf{\hat y}\textrm{ N}) = -11.5\,\mathbf{\hat x}\wedge\mathbf{\hat y}\textrm{ Nm}$$So the magnitude of the torque is
The net torque about an axis of rotation is equal to the product of the rotational inertia about that axis and the angular acceleration, as shown in Figure 1. Similar to Newton's Second Law, angular motion also obeys Newton's First Law....
The formula for determining torque, τ is τ = r × F, where r is the lever arm and F is the force. Remember, r, τ, and F are all vector quantities, thus the operation is not scalar multiplication, but a vector cross product.