Find the next 3 terms of sequences given below- i)2,5,11,23... ii)2,4,8,16...
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Answered by
1
i) 2 .5.11.23..... the difference is 3,6,12..... means double of previous difference.
so next difference will be 24, 48, 96 and terms will be
23 +24 = 47
47+48 = 95
95+ 96 = 191
ii)2,4,8,16..... difference is 2,4,8 ....means again the double of previous difference.
so next difference will be 16, 32, 64
so the terms will be,
16+16 = 32
32 +32 =64
64+64 = 128
so next difference will be 24, 48, 96 and terms will be
23 +24 = 47
47+48 = 95
95+ 96 = 191
ii)2,4,8,16..... difference is 2,4,8 ....means again the double of previous difference.
so next difference will be 16, 32, 64
so the terms will be,
16+16 = 32
32 +32 =64
64+64 = 128
qais:
corrected miss :)
thanks :)
Answered by
1
(1). Next number in the sequence just arrive by doubling the preceeding number and there by adding 1 to it.
2, 5 (2x2+1), 11 (5x2+1), 23 (11x2+1)..next no.s be (23x2+1) 47, (47x2+1) 95, (95x2+1)191....
2, 5, 11, 23, __47, 95, 191___ is the sequence
======@@@========
(2) The sequence just followed the rule 2^n (2 power n), where n=1,2,3,4,5,6,7,....
2 (2^1), 4 (2²), 8 (2³), 16 (2^4).. next no.s will be (2^5) 32, (2^5) 64, (2^6) 128
So the sequence be 2,4,8,16,__32,64,128__
2, 5 (2x2+1), 11 (5x2+1), 23 (11x2+1)..next no.s be (23x2+1) 47, (47x2+1) 95, (95x2+1)191....
2, 5, 11, 23, __47, 95, 191___ is the sequence
======@@@========
(2) The sequence just followed the rule 2^n (2 power n), where n=1,2,3,4,5,6,7,....
2 (2^1), 4 (2²), 8 (2³), 16 (2^4).. next no.s will be (2^5) 32, (2^5) 64, (2^6) 128
So the sequence be 2,4,8,16,__32,64,128__
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