find the next 4 term of an sequence 1/6, 1/4,1/3 and also find sn
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Answer:
T1=a=1/6. T2=1/4. T3=1/3
a= 1/6
d= T2-T1
=1/4-1/6
=6-4/6×4
= 2/ 24
= 1/12
d=T3-T2
= 1/3-1/4
= 4-3/3×4
=1/1
formula of sum
Sn= n(n+3)/24
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