Question

find the next for the equation (2 + x) (7 - X) divide (5 - x) 4 + x is equal to 1 ​

Answer 1

$\sf \frac{(2 + x)(7 - x)}{4(5 - x) + x} = 1$

$\sf (2 + x)(7 - x) = 1 \lgroup4(5 - x) + x \rgroup$

$\sf 14 - 2x + 7x - {x}^{2} = 20 - 4x + x$

so,

$\sf14 + 5x - {x}^{2} = 20 - 3x$

$\sf {x}^{2} - 8x - 6 = 0$

BY €QUATTING ,

The value of x is

$\sf x = \frac{64 + \sqrt{208} }{2} \: \: , \: \: \frac{64 - \sqrt{208} }{2}$

Answer 2

Answer:

(2+x)(7-x) = 14-2x+7x-x^2 = - x^2+5x+14

(5-x)4+x = 20-4x+5x-x^2 = -x^2+x+20

Divide -x^2+5x+14 by -x^2+x+20 is equal to 1