Question

Find the next two terms of the
arithmetic progression v 14, V 56,
✓ 126 V 224.....​

Answer 1

Answer:

$\sqrt{14} ; \sqrt{56};\sqrt{126};\sqrt{224}...................$

$\sqrt{14};2\sqrt{14};3\sqrt{14};4\sqrt{14}............$

a = $\sqrt{14}$

d = $2\sqrt{14}-\sqrt{14}=\sqrt{14}$

$t_{4} = 4\sqrt{14}$

$t_{5} = t_{4} + d\\\\t_{5} = 4\sqrt{14}+\sqrt{14} = 5\sqrt{14} = \sqrt{350}$

$t_{6} = t_{5} + d \\\\t_{6}= 5\sqrt{14} +\sqrt{14}=6\sqrt{14}=\sqrt{504}$

therefore the next 2 terms of this AP are :-

$\sqrt{305};\sqrt{504}..........$

$\sqrt{14} ; \sqrt{56};\sqrt{126};\sqrt{224};\sqrt{305};\sqrt{504}..........$