Find the no. In ap whose sum is 21 and product is 315
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Answer:
Step-by-step explanation:
according to question ..
(a+a+d)=21 ; *equation 1 ;
(a*(a+d))=315 ; *equation 2;
so
from equation 1 ;
2*a+d=21 ;
d=21-2*a ;
now putting the value of d in equation 2 ;
(a*(a+21-2*a))=315 ;
(a*(21-a))=315 ;
21*a-a*a=315 ;
a*a-21*a+315 =0 ;
remark == use quadratic equation you will find imaginary roots and put it in equation 1 or 2 to get value of d ;
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