Math, asked by shubhamchhabra8938, 1 year ago

Find the no nearest to 300000 but greater than 300000 which is exactly divisible by 12 15 and 21

Answers

Answered by DSamrat
3

hey \\  \\ here \: is \: the \: answer. \\  \\ lcm \: of \: 12 \:  \: 15 \:  \: 21  = 420 \\  \\ now \: dividing \: 300000 \: by \: 420 \\  \\ we \: get \: 714 \: as \: quotient \: and \: some \: reminder \\  \\ so \:  \: no. \: greater \: than \: 300000 \: and \:  \\ exactly \: divisible \: by  \: 12 \:  \: 15 \:  \: 21 \:  \\ will \: leave \: a \: quotient \: of \:  \: 715 \: and \: zero \: reminder \\  \\ the \: required \: no. \: is \: 715 \times 420 = 300300. \\  \\ thanks.
Similar questions