find the no of aluminium ions present in 0.o501 g of aluminium oxide
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Molecular weight of Al2O3 = 102 g
102 g of Al2O3 contains 6.022X1023 molecules
0.051g of Al2O3 contain X number of molecules
X = 0.051 X 6.022X1023 /102 = 0.003 X 1020
X = 3 X 1020
1 molecule of Al2O3 contains – 2 Al+3ions
3 X 1020 molecules contains – 2 X 3 X 1020
= 6 X 1020 Al+3 ions ∴0.051 g of Al2O3 contains 6 X 1020 Al+3 ions
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- Molecular weight of Al2O3 = 102 g.
- 102 g of Al2O3 contains 6.022X1023 molecules.
- 0.051g of Al2O3 contain X number of molecules.
- X = 0.051 X 6.022X1023 /102 = 0.003 X 1020
- X = 3 X 1020
- 1 molecule of Al2O3 contains – 2 Al+3ions.
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