Question

Find the no
Of atoms molecules and ions present in 0.5 mole of caco3

Answer 1

Answer:

Given mass = 50 g

Molecular weight of CaCO3 = 100 g / mol

No. of moles (n) = Given mass (m) / Molecular weight (M)

n = 50 / 100

n = 1 / 2

n = 0.5

No. of molecules = n * 6.022 * 10²³

= 0.5 * 6.022 * 10²³

= 3.011 * 10²³

No. of atoms = 5 * 3.011 * 10²³

= 15.055 * 10²³

Answer 2

Answer:

50 g of caco3

3.011×10^23 Atoms

and to calculate ions.. you must specify more