Question

find the no. of chloride ions present in 10 moles of alcl3 where al=27u & Cl=35​

Answer 1

1 Mole of AlCl3 = 6.022×10^23 molecules

10 Moles of AlCl3 = 6.022×10^24 molecules

1 molecule has 3cl- ions so...

6.022×10^24 molecules contains ?

⇒(6.022×10^24) ×3

=18.066×10^24 Cl- ions are present in 10 moles of AlCl3