Question

find the no. of coin 2cm in diameter and0.5cm thick to be melted to form a right circular cylinder of hieght 10cm and radius 3.5cm


dont spam want answer fast plz give​

Answer 1

Answer:

$\large{\boxed{\boxed{\bf{Question}}}}$

Find the number of coin 2 cm in diameter and 0.5 cm thick to be melted to form a right circular cylinder of hieght 10 cm and radius 3.5 cm.

$\huge{\boxed{\rm{Answer}}}$

$\large{\boxed{\boxed{\bf{Given \: that}}}}$

Dimensions of coin

• Diameter of coin = 2 cm
• Radius of coin, r = 1 cm
• Thickness of coin, h = 0.5 cm

Dimensions of Cylinder

• Radius of cylinder, R = 3.5 cm
• Height of cylinder, H = 10 cm

$\large{\boxed{\boxed{\bf{To \: find}}}}$

• Number of coins

$\large{\boxed{\boxed{\bf{Solution}}}}$

Dimensions of coin

Diameter of coin = 2 cm

Radius of coin, r = 1 cm

Thickness of coin, h = 0.5 cm

Dimensions of Cylinder

Radius of cylinder, R = 3.5 cm

Height of cylinder, H = 10 cm

Let number of coins required be n.

According to statement,

$\bf \:n \times volume \: of \: coin \: = volume \: of \: cylinder$

$\bf\implies \:n \times \pi \: {r}^{2} h = \pi \: { R}^{2} H$

$\bf\implies \:n \times 1 \times 1 \times 0.5 = 3.5 \times 3.5 \times 10$

$\bf\implies \:n \: = 245$

So, number of coins required, n = 245