Find the no. of copper atom present in 10gram of 22caret gold.
Answers
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Answer:
There is 2 parts of, out of 24 parts, copper is present.
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Answer:
first of all, find the percentage of copper present in 22-carat gold.
Explaination:
percentage of copper in 22 carat gold = (24 - 22)/24 × 100 = 100/12 = 25/3 %
now,
weight of copper in 10g of 22 carat gold = 25/3 % of 10g = 25/3 × 10/100
= 10/12 g
now,
number of copper atoms in (10/12)g = number of mole of copper × Avogadro's number
= given weight/atomic mass × 6.023 × 10²³
= (10/12)/63.5 × 6.023 × 10²³
= (10 × 6.023)/(12 × 63.5) × 10²³
= 0.079 × 10²³
= 7.9 × 10²¹
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