Math, asked by victi6709, 11 months ago

Find the no of digits in 4^2013 if log2 base 10=0.3010

Answers

Answered by 8334812253shinam
6

4^2013

log2 base 10= 0.3010

let x= 4^2013

x=2^2^2013

x=2^4026

Taking log both the sides

logx = log 2^4026

logx= 4026 log 2

logx=4026 × 0.3010

log×=1211.826 ( 1211 :characteristics, 826:Mantissa)

No.of digits =characteriatics +1

=1211+1

=1212 is ur answer

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