Question

Find the no of electrons present in a charge of 10microcoulomb

Answer 1

Given ,

Charge (q) = 10 micro C or (10)^-5 C

We know that ,

The charge on a body is an integral multiples of electrons present on it

$\large \mathtt{\fbox{Charge \: (q) = ne}}$

Where ,

n = integers

e = magnitude of electron

Thus ,

(10)^-5 = n × 1.6 × (10)^-19

n = 0.625 × (10)^-19

n = 6.25 × (10)^-20

Hence , the number of electrons is 6.25 × (10)^-20