Question

find the no of electrons that should be removed from a coin so that it aquires a charge of 10to the power-6 C​

Answer 1

Answer:

Explanation:

As we know q=ne

Where q is the charge

n is the number of electrons

And e is the charge on an electron i.e 1.6×10^-19

So n=q/e =10^-6/1.6×10^-19

=6.25×10^12

Hope this helped.

Answer 2

Answer:

=6.25×10^12

Explanation:

As we know q=ne

Where q is the charge

n is the number of electrons

And e is the charge on an electron i.e 1.6×10^-19

So n=q/e =10^-6/1.6×10^-19