Question

find the no. of electrons transferred between two points be at potential difference of 20 v if 40 joule of work is done​

Answer 1

Explanation:

V=J/C

20=40/C

C=2

1C=6.25*10^6

2C=(6.25*10^6)*2

2C=12.5*10^6

So, no. of electrons transferred between two points be at potential difference of 20 v if 40 joule of work is done is 12.5*10^6 electrons.

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Answer 2

Given :

Potential difference (V) = 20 V

Work Done (W) = 40 J

To Find :

Number of electrons

Solution :

We know,

  Work Done (W) = Potential Difference (V) × Charge (Q)

or,  Charge (Q)     = $\frac{Work Done (W)}{Potential Difference (V)}$

∴ Charge (Q) = $\frac{40}{20}$ = 2 C

Now,

 Charge (Q) = No. of electrons (n) × Charge of electron (e)

⇒     2            =   n × 1.6 × 10⁻¹⁹

∴      n            =  1.25 × 10¹⁹

Therefore, the number of electrons transferred between two the points  having potential difference of 20 v is 1.25 × 10¹⁹