Question

Find the no. of electrons when 5C of change flows through the wire in 2 minute?

Answer 1

Explanation:

from quantization of charge we get

Q=ne

where n = no ofelectrons

i=Q/t

i=ne/t

n=i.t/e

n=5×2×60/1.9×10^-19

n=315.7×10^-19