Question

find the no of molecules in 28g of nitrogen?

Answer 1

Answer:

1.2046  × 10²⁴ molecules

Explanation:

No. of mole $=\frac{given\ mass}{molar\ mass}$

                         $=\frac{28}{14}$

                           = 2 moles

we know 1 mole contains 6.023 × 10²³  molecules

So, 2 moles contains = 2 ×  6.023 × 10²³ molecules

                                    = 1.2046  × 10²⁴ molecules

                           

Answer 2

Given,

Given the mass of nitrogen = 28 g

To find,

The number of molecules in 28 g of Nitrogen.

Solution,

The no of molecules in 28g of nitrogen is 1.0246 * 10²⁴.

We can solve the above given numerical by the following way

Number of moles = Given mass/Mola mass

                            = 28/14

                            = 2 moles

1 mole = 6.022 * 10²³ [Avagadro's number]

2moles = 2* 6.023 * 10²⁴

            =12.046 * 10²⁴

            = 1.2046 * 10²⁴

Hence,  the no of molecules in 28g of nitrogen is 1.0246* 10²⁴.