Find the no. Of molecules in 80g CaCO3
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How many molecules are there in CaCO3?
Numerical problems based On Mole Concept
Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3). Solution — Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g No. of moles of CaCO3 = No. of molecules/Avogadro constant = 6.022 × 1023/ 6.022 × 1023 = 1 mole Mass of CaCO3 = No.
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if 80g of calcium are present in x moles of caco3 is 10
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