Question

Find the no. of molecules present in 78g of CO2

Answer 1

Answer:

Molecular weight of CO2= 14+ 16×2= 44g/mol

Given= 78g

Now, 44g of molecules contain 6.023× 10^23 molecules.

Thus 78 grams will contain:

$\frac{6.083 \times 10 {}^{23} \times78 }{44}$

Please solve get your answer

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