find the no.of moles of benzoic acid that contain in2gm of the pure acid
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Explanation:
benzoic acid is C6H5COOH
Therefore molecular mass of benzoic acid is
=12*6+1*5+12+16+16+1
=72g
so...... 72g of benzoic acid is present in 1 mole of pure acid.
.......... 2 g of benzoic acid is present in 2/72
=1/36
= 0.0277 moles.
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