Question

find the no. of Na+ and Cl- ions present in 117grams of NaCl

Answer 1

Answer:

Explanation:

Molecular mass of NaCl= 23 + 35.5= 58.5

no. of moles of NaCl = $\frac{117}{58.5}$ = 2 moles

now, there will be two moles of Na⁺ ions and 2 moles of Cl⁻ ions