Question

Find the no of natural no between 101and 999 which are divisiblr by both 2 and 5

Answer 1

Answer:

Step-by-step explanation:

Answer.

a = 110 {first number to be divided by 2 and 5}

difference d =10

an=990  {last no to be divided by 2 and 5}

an = a + {n - 1}d

990 = 110 + 10n -10

880 + 10 = 10n

890 = 10n  

n = 89

∴ number of natural numbers between 101 and 999 is 89.