Find the no. Of natural no.s betw 102 & 998 which are divisible by 2 and 5 both
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Answer:
Divisible by 2 is 449
Divisible by 5 is 179
Step-by-step explanation:
let the 1st AP be 102,104,106......998
- a=102
- d=2
- an=998
- n=?
An=a+(n-1)d
- 998=102+(n-1)2
- 998-102=(n-1)2
- 896=(n-1)2
- 896/2=(n-1)
- 448=(n-1)
- 448+1=n
- 449=n
Let the 2nd AP be 105,110,115.....995
- a=105
- d=5
- an=995
- n=?
An=a+(n-1)d
- 995=105+(n-1)5
- 995-105=(n-1)5
- 890=(n-1)5
- 890/5=(n-1)
- 178=(n+1)
- 178+1=n
- 179
Hope this may help you
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