Math, asked by surekhamurkute1975, 9 months ago

Find the no. Of natural no.s betw 102 & 998 which are divisible by 2 and 5 both

Answers

Answered by shaheed57
1

Answer:

Divisible by 2 is 449

Divisible by 5 is 179

Step-by-step explanation:

let the 1st AP be 102,104,106......998

  • a=102
  • d=2
  • an=998
  • n=?

An=a+(n-1)d

  • 998=102+(n-1)2
  • 998-102=(n-1)2
  • 896=(n-1)2
  • 896/2=(n-1)
  • 448=(n-1)
  • 448+1=n
  • 449=n

Let the 2nd AP be 105,110,115.....995

  • a=105
  • d=5
  • an=995
  • n=?

An=a+(n-1)d

  • 995=105+(n-1)5
  • 995-105=(n-1)5
  • 890=(n-1)5
  • 890/5=(n-1)
  • 178=(n+1)
  • 178+1=n
  • 179

Hope this may help you

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