Question

find the no. of natural no.s between 101 and 999 which are divisible by both 2 and 5​

Answer 1

the first no. is=110

rhe second no. is 120

the third no. is 130

This forms and A.P : 110,120,130.......990

An= a +(n-1)d

990=110+(n-1)10

880/10=n-1

88=n-1

n=89

So 89 ia the correct answee

Answer 2

Hope my answer will help you

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