Math, asked by justa2v5laamyac, 1 year ago

Find the no. of odd positive integers with no digit repeated.

Answers

Answered by saisrinivas05
0
The answer is 325 For 5 digit number-5*4*3*2*1=120 For 4 digit number-5*4*3*2=120 For 3 digit number-5*4*3=60 For 2 digit number-5*4=20 For 1 digit number-5 Total=120+120+60+20+5=325
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