Question

find the no of oxygen atoms present in 132 g og CO2

Answer 1

Answer:

Explanation:

Molar mass of CO2, M= 44 g/mol

Given mass of CO2, m= 132 g

no. of moles, n=m/M

=132/44

=3 moles

no. of CO2 molecules in 1 mol CO2 =6.022×10^23 molecules

no. of CO2 molecules in 3 mol CO2 =6.002×10^23 × 3

=18.066×10^23 molecules

There are 2 atoms of Oxygen in 1 CO2 molecule

So, no. of O atoms in 18.066×10^23 molecules= 2×18.066×10^23

=36.132×10^23 atoms