Question

Find the no of particles present in 2g atoms of N2

Answer 1

No.od particles= weight/molecular weight

Or

in 28grams of N₂ there is 1 mole of dinitrogen

so, in 2 grams there will be--> 2/28= 0.07moles

so, no.of particles/molecules is

1mole---> avagardro no.of molecules

0.07×6.023×10²³

=0.42×10²³ molcules/particles

Answer 2

given mass = 2g
molar mass of N2= 14*2=28
no. of moles = given mass / molar mass
= 2/28 =1/14
we know that no of molecules in 1 mole of something = 6.022*10^23
no. of molecules in 2 g of N2 gas = 6.022*10^23 * 1/14
= about 4.301*10^22
if it is correct please mark brainliest