Question

find the no of sides in a polygon if the sum of its interior angles is 900​

Answer 1

Answer:

ANSWER IS:11

Step-by-step explanation:

EVERY QUADRILATERAL SUM OF ITS ANGLES =360(4 SIDES )

900-360 (4 SIDES)

=540

540-360(4 SIDES)

=180(3 SIDES OF TRIANGLE )

SO 4+4+3=11.

Answer 2

Answer:

7

Step-by-step explanation:

we know that the sum of the interior angles of a polygon with n sides is given by $(n-2)$ × 180.

therefore here  $(n-2)$ × 180 = 900

⇒ $(n-2)$ = 5

∴ $n=7$