Find the no. of sides of a polygon if the sum of its interior angles is 540degree
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1
Here is your answer mate
If n are number of sides of a convex polygon, sum of its interior angles is (n−2)×180∘
As in given case sum of interior angles is 540∘, we have
(n−2)×180∘=540∘
or n−2=540/180=3
and n=3+2=5
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If n are number of sides of a convex polygon, sum of its interior angles is (n−2)×180∘
As in given case sum of interior angles is 540∘, we have
(n−2)×180∘=540∘
or n−2=540/180=3
and n=3+2=5
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sum of angles= 180 ( n -2 ),
where, n= no. of sides
so, 540 = 180 (n - 2 )
540 = 180n - 360
540 + 360 = 180n
900 = 180n
n = 900/180
= 5
no. of sides= 5
where, n= no. of sides
so, 540 = 180 (n - 2 )
540 = 180n - 360
540 + 360 = 180n
900 = 180n
n = 900/180
= 5
no. of sides= 5
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