Question

Find the no. of trailing zeroes in (23!+24!+26!)

Answer 1

23! + 24! + 25! = 72!

72/5 = 14 ( in 72 14 fives are there)

72/25 = 1 ( in 72 only one 25)

So no of zeros = 14 + 1 = 15

Answer 2

We have to look like more number of N.

There are trailing zeroes is the Power of 10 in the expression onward and more number of times N is divisible by 10.

There are divisible by 10 with available for divide in 2 & 5.

We know about the zero at the end, both a and b should be at least 1.