find the no. of two digit numbers which are divisible by 6
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Answered by
11
Two digits no are
12,18,24.................96
Tn=a+(n-1)d
96=12+(n-1)6
96-12=(n-1)6
84/6=n-1
n-1=14
n=14+1
n=15
there are fifteen two digit number that are divisible by 6
mark it brainliest
please
12,18,24.................96
Tn=a+(n-1)d
96=12+(n-1)6
96-12=(n-1)6
84/6=n-1
n-1=14
n=14+1
n=15
there are fifteen two digit number that are divisible by 6
mark it brainliest
please
Answered by
2
HEY MATE HERE IS YOUR ANSWER
The no which are divisible by 6 are 12 to 96
12 ,18, 24,...........96
a=12
d=6
an=96
an=a+(n-1)d
96=12+(n-1)6
96-12=6n-6
84+6=6n
90=6n
n=15
no of digits =n+1
15+1 =16
16 no are divisible
HOPE IT HELPS YOU
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The no which are divisible by 6 are 12 to 96
12 ,18, 24,...........96
a=12
d=6
an=96
an=a+(n-1)d
96=12+(n-1)6
96-12=6n-6
84+6=6n
90=6n
n=15
no of digits =n+1
15+1 =16
16 no are divisible
HOPE IT HELPS YOU
FOLLOW ME FOR ANY OTHER QUESTIONS
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