find the no. of zeroes in the polynomial p( x ) = 3x^2 + 2x - 1
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Step-by-step explanation:
3x² +2x-1
3x² +( 3-1)x -1 =0
3x² +3 x -x -1 =0
3x ( x +1)-1( x+1) =0
( 3x -1) ( x+1) =0
3x-1=0 ; x +1=0
x =1/3 ; x = -1
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