Find the no of zeros in the product of 1^1*2^2*3^3*…..*49^49
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Answer =250
0 will be produced when an even number be multiplied by 5
or a num multiplied by 10
now 10^10=10 0's
20^20= 20 0's
30^30=30 0's
40 ^40=40 0's
5^5=5 0's
15^15=15 0's
35^35=35 0's
45^45=45 0's
but 25^25 can be written as
5^25*5^25=50 0's
summing up 250 0's
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