Question

find the no.of zerosforx^2-1​

Answer 1

Answer:

there are 2 zeroes

x^2-1 = ( x+1) ( x -1) = 0

x = -1 , 1

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Answer 2

Answer:

hey mate ❤️.....here is your answer....

x^2-1

=x^2-1^2

=(x+1)(x-1)

according to the question,

(x+1)(x-1)=0

=>(x+1)=0 or =>(x-1)=0

=>x=(-1). =>x=1

so,

the zeroes of the polynomial x^2-1 is 1 and (-1)

Step-by-step explanation:

hope this help u✌️....,mark as brainliest dear ❤️......

Thanks for asking mate ☺️