Find the
no positive
12
dum of the first
integers divisible
divisible by
6
Answers
Answered by
0
Answer:Let the number be x.
(2x/3) = (x/3)+3, or
(2x/3) = (x/3)+(9/3), or
2x-x = 9, or
x = 9.
Check: (2/3) of 9 is 6 which is (1/3)*9+3 = 6. Correct
Step-by-step explanation:
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