Question

Find the non negative real roots of the quadratuic equvation 3xsquar-5x-2=0

Answer 1

Step-by-step explanation:

The given equation is not in the form to apply the method of completing squares. The coefficient of x2 is not 1.

To make the coefficient 1, we need to divide the whole equation by 3.

x2 – 5/3 x + 2/3 = 0

Comparing with the standard form of the equation

Stand form of equation is

ax2 + bx + c = 0, where a,b and c are real numbers such that a ≠ 0 and x is a variable.

b = -5/3; c = ⅔

c – b2/4 = ⅔ – [(5/3)2/4] = ⅔ – 25/36 = -1/36

So,

= (x – 5/6)2 = 1/36

= (x – 5/6)= ± √(1/36)

= x – 5/6 = ±1/6

= x = 1, -2/3

Answer

Hence the roots of the equation are x = 1, -2/3