Question

find the non zero value of k for which the quadratic equation x²+1-2(k-1)x+x²=0 has equal roots

Answer 1

Answer:

2X + 1= k

Step-by-step explanation:

X^2 +X^2-X(k-1)=0

2X^2=KX-X

so k = 2X+1

Answer 2

Answer:

K = 12

Step-by-step explanation:

Let a and b are the zeroes of the polynomial

Again given, the sum of the squares of zeroes of the quadratic polynomial = 40

=> a2 + b2 = 40

=> (a + b)2 - 2ab = 40

=> 82 - 2ab = 40 {from the polynomial}

=> 64 - 2ab = 40

=> 2ab = 64 - 40

=> 2ab = 24

=> ab = 24/2

=> ab = 12

Now, product of the roots = k/1

=> 12 = k/1

=> k = 12

So, the value of k is 12