Question

Find the non zero value of k for which the quadratic equation kx square + 1 - 2 into k - 1 x + x square is equal to zero has equal roots hence find the roots of equation

Answer 1

Answer:

Step-by-step explanation:

given: kx2 + 1-2(k-1)x + x2

sol;

=kx2 + x2 -2(k-1) +1

x2 (k+1) - 2(k-1) +1

here,

a=(k+1)   b= -2(k-1) & c= 1

for real and equal roots;

D=0

=b2- 4ac=0

Putting the values of a.b and c

[-2(k-1)]2 - 4 (k+1)(1)=0

then on opening the brackets we'll get;

(4k)(k-3)=0

=   4k=0             and        (k-3)=0

=     k=0               or           k=3

\