Find the normal vector n to the plane, containing vectors: A = 3i +j - k and B = -i +k.
Answers
Answered by
0
normal vector perpendicular to both plane .
hence vector n= +_(cross product of two plane )
=+_{(3i+j-k) x (-i +k)}
=+_{3(-j) +k+i +j }
=+_( i -2j +k)
e.g i -2j + k and -i +2j-k are normal which is perpendicular to both plane
hence vector n= +_(cross product of two plane )
=+_{(3i+j-k) x (-i +k)}
=+_{3(-j) +k+i +j }
=+_( i -2j +k)
e.g i -2j + k and -i +2j-k are normal which is perpendicular to both plane
Similar questions