Question

find the normality and molarity of 5%NaOH solution

Answer 1

5% solution means 5 grams of NaOH is present in 100 ml of solution
weight of solute = 5gms
volume of solute =100 'll
molarity=weight of solute/G.M.W ×1000/100
M=5/40×1000/100
=1.25M
normality=w/G.E.W ×1/V
N=5/40×1000/100
=1.25N

Answer 2

Concept:

A combination of molarity can be used to describe normality. Molarity, on the other hand, relates to the concentration of a substance or ion in a solution, whereas normality simply refers to the molar concentration of the solution's acid or basic components.

Given:

% of NaOH solution = 5%

Find:

Find the normality and molarity of 5%NaOH solution

Solution:

5% NaOH solution can be expressed as W/W or W/V. Therefore, it is considered W/V.

Thus,

Mass of NaOH = 5 g

Volume of solution = 100 mL = 100 * 10⁻³ L = 0.1 L

The molarity of the given solution can be calculated as:

Molarity of 5% NaOH solution = number of moles of NaOH (n) / volume of solution in liters (V)

Number of moles (n)= mass of compound (m) / Molar mass of compound (M)

By substituting the number of moles in the molarity expression, we get:

Molarity of 5% NaOH solution = {mass of compound (m) / Molar mass of compound (M)} / volume of solution in liters (V)

= (5 g / 40 g/mol) / 0.1 L

= 0.0125 mol/L

= 0.0125 M

Now, the normality of the given solution can be calculated as:

Normality = Molarity * Molar mass / Equivalent mass

By substituting the given values in the above expression, we get the normality of the solution as follows below:

Normality = 0.0125 M * 40 g/mol / 40 g/mol

= 0.0125 N

Hence, the normality and molarity of the 5% NaOH solution are 0.0125 N and 0.0125 M respectively.

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