Question

Find the normalization transformation that maps a window whose lower left corner is at (1, 1) and upper right corner is at (3, 5) onto a viewport that is the entire normalized device screen.

Answer 1

Explanation:

The window parameters are following - WX-min = 1, WY-min = 1, WX-max = 3, WY-max = 5. The View parameters are following -VX- min = 0, VY-min = 0, VX-max = 1, VY-max = 1.  Sx = (VXmax- VXmin)/ WXmax and Sy = (VYmax- VYmin)/( WYmax- WYmin).  Sx= ½ and Sy = ¼.  Hence N = (1/2 0 0, 0 ¼ 0, -1/2 -1/4 1).