Math, asked by khadimhussain2048, 2 months ago

find the nth deravative of cos(x)cos(2x)cos(3x)​

Answers

Answered by Anonymous
1

Step-by-step explanation:

ANSWER

I=∫cosx⋅cos2x⋅cos3xdx

=∫

2

1

(2cosx⋅cos3x)cos2xdx

=∫

2

1

(cos4x+cos2x)cos2xdx

=∫

2

1

(cos4x⋅cos2x+cos

2

2x)dx

=∫

4

1

(2cos

4

x⋅cos2x+2cos

2

2x)dx

=

4

1

∫(cos6x+cos2x+2cos

2

2x)dx

=

4

1

∫(cos6x+cos2x+cos4x+1)dx

=

4

1

[

6

sin6x

+

2

sin2x

+

4

sin4x

+x]+c.

Answered By

toppr

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