Math, asked by naresh95388, 1 year ago

find the nth derivative

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Answered by jacobcunningham202
0

The nth Derivative of a Function


Let f:[a,b]→R be differentiable. Then f′(x) exists and is itself a function. It is very possible that f′ is also differentiable and we can differentiate f′ to get (f′)′=f′′.


Definition: Let f:[a,b]→R be differentiable. If f′ is also differentiable then f is said to be 2-times Differentiable its derivative is called the Second Derivative of f and is denoted f′′=(f′)′.



We can define an n-times differentiable function and the nth derivative of f, denoted f(n), similarly, provided that the previous derivatives exist.



For example, if f(x)=x3 then f′(x)=3x2 and f′′(x)=[f′(x)]′=[3x2]′=6x.


Theorem 1: If f is a polynomial of degree n then f(n) is a constant function and f(n+1) is the zero function.



   Proof: Let f be a polynomial of degree n. Then f has the form:



(1)


f(x)=a0+a1x+...+anxn



   If we differentiate f we get:



(2)


f′(x)=a1+2a2x+...+nanxn−1



   So differentiating a polynomial reduces the degree of all of its terms by 1. So f(n) will be a constant. Namely:



(3)


f(n)(x)=n!an



   And furthermore, f(n+1)(x)=0 since the derivative of a constant is equal to 0.

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