Find the nth derivative of sin^3 x
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Left f(x) = x³ and g(x) = sin(x)
Therefore your function written as a composition of functions is:
f(g(x)) = sin³(x)
Then the chain rule says that its derivative should be:
f'(g(x))g'(x)
Therefore, your answer is:
dy/dx = 3sin²(x)cos(x)
Therefore your function written as a composition of functions is:
f(g(x)) = sin³(x)
Then the chain rule says that its derivative should be:
f'(g(x))g'(x)
Therefore, your answer is:
dy/dx = 3sin²(x)cos(x)
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