Math, asked by lavishasingla74, 7 months ago

find the nth derivative of sin²x

Answers

Answered by mw6775055
0

Answer:

nth derivative of sin²x

Step-by-step explanation:

Y=Sin²x=(1-cos2x)/2

Y¹= sin2x

Y²=-2cos2x

Yn= - 2^(n-1) × cos(2x+nπ/2)

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